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Simplification

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medium importance~2 Q in Tier 126 formulas⚡ 14 shortcuts5 subtopics

BODMAS, 'of', brackets & vinculum

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Order of operations (VBODMAS):

  1. Vinculum (bar) — e.g. 5−3‾\overline{5-3}
  2. Brackets, innermost first: ( ) → { } → [ ]
  3. Of (a multiplication that is done before ÷ and ×)
  4. Division and Multiplication — left to right
  5. Addition and Subtraction — left to right

The key CGL trap is 'of': 64÷4 of 2=64÷8=864 \div 4 \text{ of } 2 = 64 \div 8 = 8, but 64÷4×2=3264 \div 4 \times 2 = 32.

Continued fractions are simplified from the bottom up. A minus sign before a bracket flips every sign inside it.

Detailed notes

What is VBODMAS?

When a long expression has +,−,×,÷+, -, \times, \div, brackets and bars, every calculator (and every examiner) follows one fixed order, called VBODMAS:

  1. V — Vinculum: a bar over an expression, like 9−7‾\overline{9-7}, is cleared first.
  2. B — Brackets: innermost first: ()( ) then {}\{ \} then [][ ].
  3. O — Of: 'of' means multiply, but it is done before ÷ and ×.
  4. D and M: divisions and multiplications, strictly left to right.
  5. A and S: additions and subtractions, again left to right.

The 'of' trap

64÷4 of 264 \div 4 \text{ of } 2 is 64÷8=864 \div 8 = 8, not (64÷4)×2=32(64 \div 4) \times 2 = 32. Compare: 64÷4×2=16×2=3264 \div 4 \times 2 = 16 \times 2 = 32 — no 'of', so left to right. Another form: 34\frac{3}{4} of 48÷248 \div 2 = (34×48)÷2=18(\frac{3}{4} \times 48) \div 2 = 18, because 'of' groups 4848 with 34\frac{3}{4} before any ÷\div outside.

Working through brackets

Always start from the innermost bracket. A minus sign in front of a bracket flips every sign inside: 25−(10−6)=25−10+6=2125 - (10 - 6) = 25 - 10 + 6 = 21. With three layers, clear ()( ), then {}\{ \}, then [][ ], one at a time. Do not try to open all brackets in one go.

Continued fractions

A fraction written inside a fraction, like 1+11+121 + \cfrac{1}{1 + \cfrac{1}{2}}, is simplified from the bottom up:

  • bottom: 1+12=321 + \frac{1}{2} = \frac{3}{2}
  • next: 13/2=23\frac{1}{3/2} = \frac{2}{3}
  • top: 1+23=531 + \frac{2}{3} = \frac{5}{3}.

Left-to-right chains

When only ÷\div, ×\times (and later +,−+, -) appear, work strictly left to right: 60÷5×3=12×3=3660 \div 5 \times 3 = 12 \times 3 = 36, not 60÷15=460 \div 15 = 4.

Two speed tools

  • Digit-sum check (casting out 9s): replace each number by its digit sum (9 becomes 0), do the same operations on the digit sums, and compare with the digit sum of each option. It catches most slips. Example: 48+36=8448 + 36 = 84; digit sums 3+0=33 + 0 = 3, and 84→384 \to 3 ✓.
  • Last-digit check: for ×\times and ++ chains, the option's last digit must match the last digit you get by working only with last digits. 7×8+6=627 \times 8 + 6 = 62; last digits 6+6=12→26 + 6 = 12 \to 2 ✓.

Approximate placement of values

Some questions ask "what comes in place of ?". Replace the ? by each option only after simplifying the fixed parts — do not solve with algebra when a check of two options is faster.

Quick revision

  • Order: vinculum → brackets → of → ÷/× (L→R) → +/− (L→R).
  • 'of' beats ÷ and ×.
  • Minus before a bracket flips signs inside.
  • Continued fractions: bottom-up.
  • Verify with digit sums or last digits.

Types of questions asked

Every way this subtopic shows up in exams — how to recognise it, the formula or logic to use, and a solved example.

Type 1: 'of' before ÷ and × (including % of and missing value)very common3 practice Q
How to spot it:

The expression mixes ÷\div, ×\times and 'of' (or '% of'). Often '?' sits in place of one number.

a÷b of c=a÷(b×c)a \div b \text{ of } c = a \div (b \times c)
  1. Replace every 'of' by a bracket: 4 of 3→(4×3)4 \text{ of } 3 \to (4 \times 3).
  2. Then do ÷ and × left to right, then + and −.
  3. For a missing value, simplify the rest first and solve the small equation.

Why: 'of' is a multiplication that examiners rank above ÷ and ×.

Example: Evaluate 64÷4 of 2+8×364 \div 4 \text{ of } 2 + 8 \times 3.

4 of 2=84 \text{ of } 2 = 8; 64÷8=864 \div 8 = 8; 8×3=248 \times 3 = 24. Total 8+24=328 + 24 = 32. (Wrong: (64÷4)×2=32(64 \div 4) \times 2 = 32 → 5656.)

Type 2: Vinculum and three-layer bracketsvery common2 practice Q
How to spot it:

An expression with a bar over some digits and ( ), { }, [ ] nested inside each other.

  1. Clear the vinculum (bar) first.
  2. Then the round bracket, then curly, then square.
  3. A minus in front of a bracket flips every sign inside it.

Why: each layer must become a single number before the layer outside it can act.

Example: Simplify 25−[12−{8−(7−9−5‾)}]25 - [12 - \{8 - (7 - \overline{9 - 5})\}].

Bar: 4. Round: 7 − 4 = 3. Curly: 8 − 3 = 5. Square: 12 − 5 = 7. Answer 25−7=1825 - 7 = 18.

Type 3: Continued (nested) fractionscommon2 practice Q
How to spot it:

Fractions stacked inside fractions, often written with cfrac in the paper as small 1s stacked.

simplify from the bottom upwards\text{simplify from the bottom upwards}
  1. Start with the deepest (bottom) fraction and make it a single number.
  2. Move one layer up, repeat.
  3. The last step gives the value; keep fractions, not decimals.

Why: a fraction line is a division in disguise, and the deepest division must happen first.

Example: Find 1+11+11+131 + \cfrac{1}{1 + \cfrac{1}{1 + \cfrac{1}{3}}}.

1+13=43→34→1+34=74→47→1+47=1171+\frac13=\frac43 \to \frac{3}{4} \to 1+\frac34=\frac74 \to \frac47 \to 1+\frac47=\frac{11}{7}.

Type 4: Long ÷ × + − chains (left to right)very common2 practice Q
How to spot it:

A plain chain like 96÷8×4+12×2÷3−1096 \div 8 \times 4 + 12 \times 2 \div 3 - 10 with no 'of' and no brackets.

÷ and × share a level: go left to right\div \text{ and } \times \text{ share a level: go left to right}
  1. Walk through the expression once, left to right.
  2. Do only ÷ and × in this pass (as they come).
  3. Then do + and − in a second left-to-right pass.

Why: ÷ and × have equal rank; the leftmost one acts first.

Example: Simplify 60÷5×3−18÷6×2+760 \div 5 \times 3 - 18 \div 6 \times 2 + 7.

60÷5=1260 \div 5 = 12, ×3=36\times 3 = 36; 18÷6=318 \div 6 = 3, ×2=6\times 2 = 6; 36−6+7=3736 - 6 + 7 = 37.

Type 5: Full mixed expression (Tier-2 style, with fractions and %)common2 practice Q
How to spot it:

A longer question mixing 'of', brackets, a fraction term and a percentage term.

x% of N=x100×Nx\% \text{ of } N = \frac{x}{100} \times N
  1. Turn 'of' terms into products, percentages into fractions of 100.
  2. Simplify each term separately, then combine.
  3. Keep fractions (like 3/11 of 1331) exact — they usually divide neatly.

Why: term-by-term simplification avoids one giant unreadable line.

Example: Simplify 311\frac{3}{11}  of \text{ of } 1331−25%1331 - 25\%  of \text{ of } 160+13160 + 13.

363−40+13=336363 - 40 + 13 = 336.

Formulas

'of' before division
a÷b of c=ab×ca \div b \text{ of } c = \frac{a}{b \times c}
÷ and × left to right
a÷b×c=ab×ca \div b \times c = \frac{a}{b} \times c
Removing a bracket after minus
a−(b−c)=a−b+ca - (b - c) = a - b + c
Continued fraction (bottom-up)
a+1b+1c=a+cbc+1a + \cfrac{1}{b + \cfrac{1}{c}} = a + \frac{c}{bc + 1}

Shortcut tricks

⚡ 'of' binds tighter than ÷

Convert every 'of' into a bracketed product before touching ÷.

Example: Evaluate 64÷4 of 264 \div 4 \text{ of } 2.

4 of 2=84 \text{ of } 2 = 8, so 64÷8=864 \div 8 = 8 (not 16×2=3216 \times 2 = 32).

⚡ Continued fractions bottom-up

Start with the lowest fraction, invert and add step by step.

Example: Evaluate 2+12+12+122 + \cfrac{1}{2 + \cfrac{1}{2 + \frac{1}{2}}}.

2+12=522 + \frac{1}{2} = \frac{5}{2} → 2+25=1252 + \frac{2}{5} = \frac{12}{5} → 2+512=29122 + \frac{5}{12} = \frac{29}{12}.

⚡ Digit-sum (casting out 9s) option check

Digit sum of a product = digit sum of (digit sum × digit sum). Kills wrong options in long multiplication without computing.

Example: Which could be 3456×7893456 \times 789: 2726784 or 2726874 or 2762784?

Digit sums: 3456 → 9, 789 → 6, so product ≡ 9 × 6 = 54 → 9. 2+7+2+6+7+8+4 = 36 → 9 ✓. The other two also give 36 — so combine with the unit digit (6 × 9 = 54 → 4) and magnitude; exact value 2726784.

Where students lose marks

  • Doing a÷b×ca \div b \times c as a÷(b×c)a \div (b \times c).

  • Ignoring 'of' and treating it like ordinary ×, which is done after ÷.

  • Not removing the vinculum (bar) first.

  • Forgetting to flip signs when removing a bracket preceded by a minus.

Practice sets — 13 questions

Sets of 10, mixed across the question types above. Each answer comes with a step-by-step explanation.

Topic test · 13 questions

Suggested time 10 min · wrong answers go to your mistake notebook automatically.