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Counting Figures

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medium importance~0-1 Q in Tier 14 formulas⚡ 4 shortcuts3 subtopics

Counting triangles

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Never count by eye. Use one of two systematic methods:

  1. Size-by-size: count the smallest triangles, then triangles made of 2 pieces, then 3, and so on. Symmetric figures (square with diagonals) are fastest this way.
  2. Vertex labelling: name every corner and crossing point, then list triangles by their top vertex. Slow but fool-proof for irregular figures.

Formula for a triangle with lines from the apex: if k lines are drawn from the apex to the base (splitting it into k + 1 parts), the number of triangles is (k + 1)(k + 2) ÷ 2 — it equals the number of ways to pick two of the k + 2 lines through the apex. Every horizontal line cutting all of them adds another full set: multiply by (h + 1).

Detailed notes

What the question asks

You get a line drawing and must say how many triangles are hidden in it. A triangle is any closed shape with exactly three straight sides. The sides may be made of several small drawn pieces joined in a straight line. Small triangles, medium ones made of several pieces, and the big outer triangle all count.

Think of a samosa cut by a knife. Each cut makes new small pieces, but a big piece made of two small pieces is still a triangle. Most wrong answers come from missing these bigger joined triangles.

Method 1: size by size

  1. Count the smallest triangles (the ones with no line inside).
  2. Count triangles made of 2 pieces, then 3 pieces, then 4, and so on.
  3. Do not forget the whole figure if it is itself a triangle.
  4. Add all the groups.

Example: a square with both diagonals. Smallest triangles = 4 (meeting at the centre). Triangles made of 2 pieces = 4 (each is half of the square). Total = 8.

Method 2: name the corners

Put a letter on every corner and every crossing point. Take one point at a time and list every triangle that has it as a corner, using only points joined by drawn lines. This is slow but safe for odd, irregular figures.

Ready formulas for standard figures

Lines from the apex. A triangle with k lines drawn from the top corner (apex) to the base splits the base into k + 1 parts. Every triangle here has the apex as its top and two of the lines through the apex as its sides. There are k + 2 such lines, so

T=(k+1)(k+2)2T = \frac{(k+1)(k+2)}{2}

With 3 apex lines: 4×52=10\frac{4 \times 5}{2} = 10.

Adding horizontal cuts. Each line parallel to the base that crosses all the apex lines gives one more full set. With h such lines: T=(k+1)(k+2)2×(h+1)T = \frac{(k+1)(k+2)}{2} \times (h+1). With 2 apex lines and 1 cut: 6×2=126 \times 2 = 12.

Triangle cut into rows of small triangles. A big triangle whose sides are divided into n equal parts and joined by lines parallel to the sides:

Rows n12345
Triangles15132748

Remember that upside-down triangles also count (a 3-row figure has 3 upside-down small ones).

Square with diagonals. Both diagonals: 8. Both diagonals and both midlines: 16 (8 smallest + 4 of two pieces + 4 half-squares).

Triangle with its three medians (lines from each corner to the middle of the opposite side): 16 triangles.

Pentagon with all its diagonals (a star inside a pentagon): 35 triangles. This one appears again and again, so remember it.

Special cases

  • A four-sided piece is never a triangle, even if it looks pointed.
  • Three points on one straight line do not make a triangle.
  • Two drawn pieces that lie in one straight line act as one side.
  • When a figure is symmetric, count one half and double, but add any triangle that sits across the middle line only once.

Quick revision

  • Count size by size: smallest, then 2-piece, 3-piece, and finally the whole figure.
  • Apex lines: (k+1)(k+2)/2; with h horizontal cuts multiply by (h+1).
  • Square + 2 diagonals = 8; add 2 midlines = 16.
  • Triangle rows: 1, 5, 13, 27, 48.
  • Triangle with 3 medians = 16; pentagon with all diagonals = 35.
  • Name the corners for any irregular figure.

Types of questions asked

Every way this subtopic shows up in exams — how to recognise it, the formula or logic to use, and a solved example.

Type 1: Triangle with lines from the apex (and horizontal cuts)very common3 practice Q
How to spot it:

One big triangle. Several lines start at the top corner and fall on the base. Sometimes one or two lines run parallel to the base.

T=(k+1)(k+2)2×(h+1)T=\frac{(k+1)(k+2)}{2}\times(h+1)
  1. Count k = lines from the apex (not the two sides).
  2. Count h = lines parallel to the base that cross every apex line.
  3. Triangles = (k+1)(k+2)/2 × (h+1).

Why: every triangle uses the apex and any 2 of the k + 2 lines through it; each horizontal line gives a new base for the same set.

Example: A triangle has 3 lines drawn from its apex to the base and 1 line parallel to the base cutting all of them. How many triangles are there?

k = 3 → (4 × 5)/2 = 10 triangles for one base. h = 1, so there are 2 bases. Total = 10 × 2 = 20.

Type 2: Square or rectangle with diagonals and midlinesvery common3 practice Q
How to spot it:

A square or rectangle with one or both diagonals, often with the lines joining the middles of opposite sides.

  1. Smallest triangles first (usually 4 or 8 around the centre).
  2. Triangles made of 2 pieces (a full side of the square as base).
  3. Half-squares made by each diagonal (4 of them when both diagonals are drawn).
  4. Add.

Why: these figures are symmetric, so each size comes in a set of 4.

Example: A square has both diagonals and both midlines drawn. How many triangles are there?

Smallest: 8. Two-piece triangles with a side of the square as base: 4. Half-squares: 4. Total = 8 + 4 + 4 = 16.

Type 3: Triangle divided into rows of small trianglescommon2 practice Q
How to spot it:

A big triangle filled with a honeycomb of small triangles, some pointing up and some pointing down.

  1. Find n = number of rows.
  2. Use the table 1, 5, 13, 27, 48 for n = 1 to 5.
  3. If you must count: upright triangles of each size, then upside-down ones.

Why: upright triangles of side s number (n−s+1)(n−s+2)/2; upside-down ones are rarer and are the ones people miss.

Example: A triangle is divided into 3 rows of small triangles (9 small triangles in all). How many triangles are there?

Upright: size 1 = 6, size 2 = 3, size 3 = 1 → 10. Upside-down: 3 small ones. Total = 13.

Type 4: Triangle with lines from its corners (medians and cevians)common3 practice Q
How to spot it:

A triangle with lines from one or more corners to the opposite sides, which cross inside the triangle.

  1. Label every corner and crossing point.
  2. Count triangles that use each drawn line as one side.
  3. Check the big outer triangle.

Why: the lines cross at inner points, so triangles appear at several levels; labelling stops double counting.

Example: In a triangle, all three medians are drawn (each joins a corner to the middle of the opposite side). How many triangles are formed?

6 smallest triangles around the centre. 3 made of 2 pieces (a full side as base, the centre point as top). 6 made of 3 pieces (each median cuts the big triangle into two halves). The whole triangle: 1. Total = 6 + 3 + 6 + 1 = 16.

Type 5: Irregular composite figures (house, star, pentagon)common3 practice Q
How to spot it:

A figure built from several shapes: a house (square with a roof), a star inside a pentagon, two overlapping triangles, an envelope.

  1. Break the figure into known parts (square with diagonals = 8, and so on).
  2. Count triangles fully inside each part.
  3. Count triangles that cross from one part into another.
  4. Add; confirm symmetric counts.

Why: known sub-figures give quick totals; only the crossing triangles need fresh work.

Example: A regular pentagon has all 5 of its diagonals drawn (a star inside it). How many triangles are there?

Sort by how many of the 5 outer corners a triangle uses. Three corners: any 3 corners are joined, so C(5, 3) = 10. Two corners: 20. One corner (the points of the star): 5. Total = 10 + 20 + 5 = 35.

Formulas

Apex lines
T=(k+1)(k+2)2T = \frac{(k+1)(k+2)}{2}

k lines from the apex to the base.

Apex lines + horizontal cuts
T=(k+1)(k+2)2×(h+1)T = \frac{(k+1)(k+2)}{2}\times(h+1)

h lines parallel to the base crossing every apex line.

Shortcut tricks

⚡ Square with both diagonals = 8

A square (or any rectangle) with both diagonals always has 4 small triangles meeting at the centre and 4 half-squares — 8 in total. Add midlines and it becomes 16: 8 smallest, 4 made of two, 4 half-squares.

Example: Q. How many triangles are in a square with both diagonals and both midlines drawn?

Sol. 8 smallest + 4 of two pieces (a full side of the square as base, apex at the centre) + 4 half-squares = 16.

Memorise 8 and 16; they recur inside bigger figures.

⚡ Choose-two-lines view

In a triangle with lines from the apex, each triangle is fixed by choosing its left and right side among the lines through the apex: C(k + 2, 2).

Example: Q. Apex with 4 lines to the base (base in 5 parts). Triangles?

Sol. Lines through the apex = 4 + 2 sides = 6. C(6, 2) = 15.

Count the lines through the apex, then C(n, 2).

Where students lose marks

  • Forgetting the big outer triangle.

  • Counting a four-sided region as a triangle because it looks pointed.

  • Missing triangles made of two or three small pieces.

Practice sets — 25 questions

Sets of 10, mixed across the question types above. Each answer comes with a step-by-step explanation.

Topic test · 10 questions

Suggested time 7 min · wrong answers go to your mistake notebook automatically.