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Interest (SI & CI)

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high importance~1 Q in Tier 122 formulas⚡ 15 shortcuts5 subtopics

Compound Interest

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Compound interest adds each year's interest to the principal — the amount grows geometrically.

A=P(1+R100)T,CI=A−PA = P\left(1 + \frac{R}{100}\right)^T, \qquad CI = A - P

Effective multipliers: 10% → ×11/10, 20% → ×6/5, 4% → ×26/25. Chain the multipliers instead of using the formula blindly.

Different rate each year (or gain then loss): multiply the year-wise factors: A=P(1+r1100)(1+r2100)⋯A = P\left(1+\frac{r_1}{100}\right)\left(1+\frac{r_2}{100}\right)\cdots

Fraction rates become easy through approximations: 623%=1156\tfrac{2}{3}\% = \frac{1}{15}, so 2 years at CI multiplies the money by 1615×1615\frac{16}{15} \times \frac{16}{15}.

Detailed notes

What compounding means

In compound interest (CI), each year's interest is added to the principal before the next year's interest is worked out. The interest earns interest, so the amount grows geometrically — by the same factor each year, not the same rupees. A=P(1+R100)T,CI=A−PA = P\left(1 + \frac{R}{100}\right)^T, \qquad CI = A - P

Multipliers (chips) — the everyday method

Write 1+R1001 + \frac{R}{100} as a fraction and multiply it T times:

RateChip
10%1110\frac{11}{10}
20%65\frac{6}{5}
1212%12\frac{1}{2}\%98\frac{9}{8}
614%6\frac{1}{4}\%1716\frac{17}{16}
8%2725\frac{27}{25}
CI on ₹12,000 at 10% for 2 years: 12000×1110×1110=₹14,52012000 \times \frac{11}{10} \times \frac{11}{10} = ₹14{,}520 → CI =₹2,520= ₹2{,}520.

The net-effect percentages

Two years at R% → net factor (1+R100)2\left(1+\frac{R}{100}\right)^2: 10% → 21% (not 20%); 20% → 44%; 25% → 56.25%; 5% → 10.25%. Three years at 10% → 33.1%; at 20% → 72.8%. These small tables answer "find the amount as % of P" questions instantly. A 12.5% rate is 18\frac{1}{8}: two years multiply by 8164\frac{81}{64} → amount =8164P= \frac{81}{64}P, CI =1764P= \frac{17}{64}P. Fraction chips keep everything exact — prefer them to decimals.

Fractional years and broken periods

2122\frac{1}{2} years at R% (annual compounding) = 2 full years by chips, then simple interest for the half year on the amount: ₹10,000 at 10% for 2122\frac{1}{2} years → 10000×1.1×1.1=12,10010000 \times 1.1 \times 1.1 = 12{,}100; half-year SI on it =12100×5100=605= 12100 \times \frac{5}{100} = 605 → ₹12,705. (Compounded half-yearly instead? See the half-yearly pattern — different answer, different question.)

Compounding more than once a year

  • Half-yearly: rate halves, periods double: A=P(1+R200)2TA = P\left(1 + \frac{R}{200}\right)^{2T}.
  • Quarterly: rate quarters, periods quadruple: A=P(1+R400)4TA = P\left(1 + \frac{R}{400}\right)^{4T}. ₹10,000 at 20% p.a. half-yearly for 1121\frac{1}{2} years → 3 half-years at 10%: 10000×1.13=₹13,31010000 \times 1.1^3 = ₹13{,}310. More frequent compounding always gives more interest than annual compounding at the same nominal rate.

Different rates in different years

Multiply the year-wise chips: A=P(1+r1100)(1+r2100)⋯A = P\left(1+\frac{r_1}{100}\right)\left(1+\frac{r_2}{100}\right)\cdots ₹25,000 with 10% then 20%: 25000×1.1×1.2=₹33,00025000 \times 1.1 \times 1.2 = ₹33{,}000. A year of gain and a year of loss simply use their own chips.

Scaling and finding P

CI is proportional to P (same rate and time): CI on ₹30,000 = 1.5 × CI on ₹20,000. From an amount: divide by the chips. ₹6,655 after 3 years at 10% → 66551.331=₹5,000\frac{6655}{1.331} = ₹5{,}000.

Quick revision

  • A=P(1+R/100)TA = P(1 + R/100)^T; multiply chips T times.
  • Net %: 2 years at 10% → 21%; at 20% → 44%; 3 years at 10% → 33.1%.
  • Half-yearly: R/2, 2T. Quarterly: R/4, 4T.
  • Broken period: full years by chips, then SI on the amount.
  • Different yearly rates: multiply their chips.

Types of questions asked

Every way this subtopic shows up in exams — how to recognise it, the formula or logic to use, and a solved example.

Type 1: Amount or CI by the multiplier methodvery common2 practice Q
How to spot it:

P, R and whole-year T are given; the amount or CI is asked.

A=P(1+R100)TA = P\left(1 + \frac{R}{100}\right)^T
  1. Write the chip 1+R1001 + \frac{R}{100} as a small fraction.
  2. Multiply P by the chip T times.
  3. CI = A − P.

Why: each year scales the running total by the same factor.

Example: Find the compound interest on ₹12,000 at 10% per annum for 2 years.

12000×1110×1110=1452012000 \times \frac{11}{10} \times \frac{11}{10} = 14520 → CI =₹2,520= ₹2{,}520. (SI would be ₹2,400.)

Type 2: Net per cent / fraction-rate compoundingvery common2 practice Q
How to spot it:

'A sum becomes 1.21 times in 2 years' or 'CI as a per cent of P' — the net effect of compounding.

net factor=(1+R100)2=1+2R100+R210000\text{net factor} = \left(1 + \frac{R}{100}\right)^2 = 1 + \frac{2R}{100} + \frac{R^2}{10000}
  1. Square the chip for 2 years, cube it for 3.
  2. Read the percentage: 10% → 21%, 20% → 44%, 12.5% → 26.5625% (8164\frac{81}{64}).
  3. For a given multiple, take the square root: 1.44 → chip 1.2 → 20%.

Why: compounding applies the same growth twice, so the effects multiply.

Example: A sum invested at compound interest becomes 1.44 times itself in 2 years. The annual rate is:

Chip =1.44=1.2= \sqrt{1.44} = 1.2 → 20% per annum.

Type 3: Half-yearly or quarterly compoundingvery common2 practice Q
How to spot it:

'Compounded half-yearly / quarterly' appears in the question — usually for 11 to 22 years.

A=P(1+R200)2T=P(1+R400)4TA = P\left(1 + \frac{R}{200}\right)^{2T} = P\left(1 + \frac{R}{400}\right)^{4T}
  1. Halve (or quarter) the rate and double (quadruple) the number of periods.
  2. Work the periods with chips as usual.
  3. Watch 1121\frac{1}{2} years: half-yearly means 3 periods.

Why: each compounding period uses the rate for that fraction of a year.

Example: Find the CI on ₹10,000 at 20% per annum for 1½ years, compounded half-yearly.

3 half-years at 10%: 10000×1.13=1331010000 \times 1.1^3 = 13310 → CI =₹3,310= ₹3{,}310.

Type 4: Different rates in different yearscommon2 practice Q
How to spot it:

'8% in the first year and 10% in the second, compounded annually' — sometimes a loss year too.

A=P(1+r1100)(1+r2100)⋯A = P\left(1+\frac{r_1}{100}\right)\left(1+\frac{r_2}{100}\right)\cdots
  1. Write each year's own chip.
  2. Multiply them all with P.
  3. CI = A − P (or compare with another scenario).

Why: each year compounds on the running amount at its own rate.

Example: ₹25,000 is invested at 10% for the first year and 20% for the second, compounded annually. The amount is:

25000×1.1×1.2=₹33,00025000 \times 1.1 \times 1.2 = ₹33{,}000.

Type 5: Scaling the CI (same rate, proportional principal)common2 practice Q
How to spot it:

The CI for one sum is given; the CI for another sum at the same rate and time is asked.

CI2CI1=P2P1\frac{CI_2}{CI_1} = \frac{P_2}{P_1}
  1. CI is proportional to P at fixed rate and time.
  2. Ratio the principals; scale the CI.
  3. For a changed time, apply the net-per-cent of the new period instead.

Why: every term of the CI formula is linear in P.

Example: The CI on ₹20,000 for 2 years at 10% is ₹4,200. The CI on ₹30,000 for the same period and rate is:

4200×3020=₹6,3004200 \times \frac{30}{20} = ₹6{,}300.

Formulas

Compound amount
A=P(1+R100)TA = P\left(1 + \frac{R}{100}\right)^T
Compound interest
CI=P[(1+R100)T−1]CI = P\left[\left(1 + \frac{R}{100}\right)^T - 1\right]
Year-wise multipliers
A=P×100+r1100×100+r2100×⋯A = P \times \frac{100 + r_1}{100} \times \frac{100 + r_2}{100} \times \cdots
Half-yearly compounding
A=P(1+R200)2TA = P\left(1 + \frac{R}{200}\right)^{2T}

rate halves, periods double

Quarterly compounding
A=P(1+R400)4TA = P\left(1 + \frac{R}{400}\right)^{4T}

Shortcut tricks

⚡ Multiplier chips

One chip per year; multiply. For fraction rates pick chips that cancel.

Example: Find the amount on ₹10,000 at 10% p.a. compound interest for 2 years.

10000×1110×1110=1210010000 \times \frac{11}{10} \times \frac{11}{10} = 12100, so CI = ₹2,100.

⚡ Recover P by dividing the chip

If the amount after T years is known, divide by the chip chain to get the principal.

Example: A sum amounts to ₹4,840 in 2 years at 10% p.a. CI. Find the sum.

P=4840×1011×1011=4000P = 4840 \times \frac{10}{11} \times \frac{10}{11} = 4000, i.e. ₹4,000.

⚡ Half-yearly: halve the rate, double the count

Convert the problem, then run the chips.

Example: Find the CI on ₹8,000 at 20% p.a. for 112\frac{1}{2} years, compounded half-yearly.

3 half-years at 10%: 8000×(1.1)3=106488000 \times (1.1)^3 = 10648 ⇒ CI = ₹2,648.

Where students lose marks

  • Compounding (1+R100)T\left(1 + \frac{R}{100}\right)^T when the rates differ year to year — multiply factors instead.

  • For half-yearly compounding, halving the time instead of the rate.

  • Reporting the amount A when the question asks for CI (or the reverse).

  • Using R200\frac{R}{200} but forgetting the exponent 2T2T (or vice versa).

Practice sets — 13 questions

Sets of 10, mixed across the question types above. Each answer comes with a step-by-step explanation.

Topic test · 13 questions

Suggested time 8 min · wrong answers go to your mistake notebook automatically.