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Data Interpretation

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medium importance~2 Q in Tier 116 formulas⚡ 10 shortcuts5 subtopics
Subtopic 5 of 5·← Averages from data

Growth rates and successive changes

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  • Growth rate: new−oldold×100\frac{\text{new}-\text{old}}{\text{old}}\times100 — same as percentage change.
  • Successive changes multiply: +a%+a\% then +b%+b\% gives the factor (1+a100)(1+b100)\left(1+\frac{a}{100}\right)\left(1+\frac{b}{100}\right). A +20%+20\% then −10%-10\% run nets 1.2×0.9=1.081.2\times0.9=1.08, i.e. +8%+8\%.
  • Running backwards: earlier value =final valuegrowth factor=\dfrac{\text{final value}}{\text{growth factor}} — divide, don't subtract.

Detailed notes

Growth = percentage change with a direction

When a table shows how one quantity moves year after year, each year-on-year jump is a growth rate: g=new−oldold×100g = \frac{\text{new} - \text{old}}{\text{old}} \times 100 Revenue going 80 → 96 crore grows 1680×100=20%\frac{16}{80} \times 100 = 20\%. A negative gg is a decline. The base is always the earlier year.

Successive changes multiply — never add

A rise of a%a\% multiplies the value by (1+a100)\left(1 + \frac{a}{100}\right); a fall of b%b\% multiplies by (1−b100)\left(1 - \frac{b}{100}\right). Two changes in a row multiply: net factor=(1+a100)(1+b100)\text{net factor} = \left(1 + \frac{a}{100}\right)\left(1 + \frac{b}{100}\right)

  • +10%+10\% then +10%+10\%: 1.1×1.1=1.211.1 \times 1.1 = 1.21 → net +21%+21\%, not +20%+20\%.
  • +25%+25\% then −20%-20\%: 1.25×0.8=1.001.25 \times 0.8 = 1.00 → net zero — a fall of 20% exactly cancels a rise of 25%.
  • Revenue 80 → 96 → 120 → 144: factors 1.2×1.25×1.2=1.81.2 \times 1.25 \times 1.2 = 1.8, so the total growth is +80%+80\%.

Running backwards

If the final value is known and the initial is asked, divide by the factor — never subtract percentages. initial=finalfactor\text{initial} = \frac{\text{final}}{\text{factor}} A salary became ₹45,000 after raises of 20% and 25%: original =450001.2×1.25=450001.5=₹30,000= \frac{45000}{1.2 \times 1.25} = \frac{45000}{1.5} = ₹30{,}000. A population of 14,400 after falls of 20% and 10%: original =144000.8×0.9=144000.72=20,000= \frac{14400}{0.8 \times 0.9} = \frac{14400}{0.72} = 20{,}000.

Profit percent from an income–expenditure table

profit%=income−expenditureexpenditure×100\text{profit}\% = \frac{\text{income} - \text{expenditure}}{\text{expenditure}} \times 100 The base is expenditure, not income — dividing by income is a standard trap. Highest profit percent is not always the year with highest profit amount: a small year can be very profitable in percentage terms.

Comparing two firms

Compare growth rates in percent, and remember a percent and a percentage point are different. Firm A grows 80% and firm B grows 100% — B is ahead by 20 percentage points, not "by 20%". Also, the bigger absolute increase can belong to the slower grower (a large base).

Worked example: a three-year chain

Revenue goes 80 → 96 → 120 → 144 (₹ crore). Year-on-year: 1680=20%\frac{16}{80} = 20\%, 2496=25%\frac{24}{96} = 25\%, 24120=20%\frac{24}{120} = 20\%. Overall factor =1.2×1.25×1.2=1.8= 1.2 \times 1.25 \times 1.2 = 1.8, so revenue is up 80%80\% over the span — although the growth rates add to 65%65\%. One multiplication settles what addition gets wrong.

Two quick self-checks

  • A rise of a%a\% followed by a fall of a%a\% always leaves a loss of a2100%\frac{a^2}{100}\%: 20% up then 20% down nets −4%-4\%.
  • If the factor chain multiplies to exactly 1, the net change is zero — the setter loves +25%+25\% with −20%-20\% and +3313%+33\tfrac{1}{3}\% with −25%-25\%.

Quick revision

  • g=new−oldold×100g = \frac{\text{new} - \text{old}}{\text{old}} \times 100; base = earlier year.
  • Chain of changes: multiply factors (1±a100)(1 \pm \frac{a}{100}).
  • +25%+25\% then −20%-20\% (or +20%+20\% then −25%-25\%) = no net change.
  • Reverse: divide the final value by the factor.
  • Profit% = profit ÷ expenditure × 100.
  • Growth comparison in percentage points = subtract the two rates.

Types of questions asked

Every way this subtopic shows up in exams — how to recognise it, the formula or logic to use, and a solved example.

Type 1: Year-on-year growth ratevery common3 practice Q
How to spot it:

'The percentage growth from year X to year Y' or 'in which year was growth highest'.

g=new−oldold×100g = \frac{\text{new} - \text{old}}{\text{old}} \times 100
  1. Base = the earlier year.
  2. Change ÷ base × 100.
  3. For 'highest growth year', compute each rate — don't compare raw jumps.

Why: growth is relative to where the year started.

Example: Revenue of firm A (in ₹ crore):

Year2020202120222023
Revenue8096120144

The percentage growth in revenue from 2020 to 2021 is:

96−8080×100=20%\frac{96 - 80}{80} \times 100 = 20\%.

Type 2: Net change over successive yearsvery common3 practice Q
How to spot it:

'The overall increase from 2020 to 2023', or mixed rise/fall statements.

factor=∏(1±ai100)\text{factor} = \prod \left(1 \pm \frac{a_i}{100}\right)
  1. Convert each year's change to a factor.
  2. Multiply the factors.
  3. Net % = (factor − 1) × 100.

Why: each change acts on the already-changed value.

Example: A price rises 10% and then another 10%. The net increase is:

1.1×1.1=1.211.1 \times 1.1 = 1.21 → net +21%+21\% (not 20%).

Type 3: Reverse growth: find the earlier valuecommon2 practice Q
How to spot it:

The final value after two or three changes is given; the original is asked.

initial=final∏(1±ai100)\text{initial} = \frac{\text{final}}{\prod \left(1 \pm \frac{a_i}{100}\right)}
  1. Build the factor chain (fall = minus).
  2. Divide the final value by the product.
  3. Keep factors as fractions for clean division.

Why: forward multiplies, backward divides.

Example: After two successive raises of 20% and 25%, a salary is ₹45,000. The original salary was:

450001.2×1.25=450001.5=₹30,000\frac{45000}{1.2 \times 1.25} = \frac{45000}{1.5} = ₹30{,}000.

Type 4: Profit percent from income and expenditurecommon2 practice Q
How to spot it:

An income–expenditure table; a profit percent asked, or the best year.

profit%=I−EE×100\text{profit}\% = \frac{I - E}{E} \times 100
  1. Profit = income − expenditure.
  2. Divide by expenditure (not income).
  3. For the best year, compute every profit percent — amounts mislead.

Why: profit percent measures return on money spent.

Example: Income and expenditure of a firm (in ₹ lakh):

YearIncomeExpenditure
2021₹60₹40
2022₹80₹50
2023₹130₹90

The profit percent in 2022 is:

80−5050×100=60%\frac{80 - 50}{50} \times 100 = 60\%.

Type 5: Comparing growth of two firms / periodscommon2 practice Q
How to spot it:

Two firms (or two spans) with start and end values; which grew faster, or by how many points.

gap in points=g1−g2\text{gap in points} = g_1 - g_2
  1. Compute each overall growth percent separately.
  2. Compare; the gap is in percentage points.
  3. Bigger absolute rise ≠ bigger percent growth.

Why: percent growth normalises for the base size.

Example: Firm A: 80 → 144. Firm B: 50 → 100 (same span). Which grew faster in percent, and by how much?

A: 80%. B: 100%. B, by 20 percentage points.

Formulas

Growth rate
g=new−oldold×100g=\frac{\text{new}-\text{old}}{\text{old}}\times100
Successive change
factor=(1+a100)(1+b100)\text{factor}=\left(1+\frac{a}{100}\right)\left(1+\frac{b}{100}\right)
Reverse growth
initial=finalfactor\text{initial}=\frac{\text{final}}{\text{factor}}
Profit percent from table
profit%=income−expenditureexpenditure×100\text{profit}\%=\frac{\text{income}-\text{expenditure}}{\text{expenditure}}\times100

Shortcut tricks

⚡ Multiply factors, never add percentages

Convert each change to a factor (+20%→1.2+20\%\to1.2), multiply, convert back. +20%+(−10%)=+10%+20\%+(-10\%)=+10\% is the classic wrong shortcut — the true net is +8%+8\%.

Example: A price rises 20% and then falls 10%. What is the net change?

1.2×0.9=1.081.2\times0.9=1.08 → net +8%+8\%.

⚡ Reverse-growth: divide by the factor

When the final value is given and the initial is asked, write the factor chain and divide once. Keep factors as fractions (1.65=33201.65=\frac{33}{20}) for clean division.

Example: A town's population grew 10%, then 20%, then 25% over three years to reach 33,000. Find the initial population.

Factor =1.1×1.2×1.25=1.65=1.1\times1.2\times1.25=1.65; initial =330001.65=20,000=\frac{33000}{1.65}=20{,}000.

Where students lose marks

  • Adding successive percentages instead of multiplying factors.

  • Reversing growth by subtracting percentages (a 25% rise then 25% fall is not flat — it is −6.25%-6.25\%).

  • Profit percent computed on income instead of expenditure.

Practice sets — 14 questions

Sets of 10, mixed across the question types above. Each answer comes with a step-by-step explanation.

Topic test · 10 questions

Suggested time 7 min · wrong answers go to your mistake notebook automatically.